4x^2+60x-351=0

Solution for 4x^2+60x-351=0 equation:

4x^2+60x-351=0

a = 4; b = 60; c = -351;
Δ = b2-4ac
Δ = 602-4·4·(-351)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-96}{2*4}=\frac{-156}{8}
=-19+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+96}{2*4}=\frac{36}{8}
=4+1/2
$